so what do you do with a set of rockers where the adjusting screw is on the pushrod end?

Peace........BartG
YesA_67vdub wrote:So, when the valve is at half lift, a line going from the center of the rocker shaft (the point that the rocker pivots on) to where the adjuster/rocker tip touches the valve should be perpendicular to the valve. Is this correct?
Halfway is a good start to give you flexibility. You understand that the adjuster only answers to the lash requirements. You have to trial & error a bit to get your shim thickness correct AT the correct lash with valve closed AND perpendicular at 1/2 lift. And yes, each change affects the others. This is the most enjoyable part of engine rebuilding . . . .A_67vdub wrote: So, how far do you screw in the adjuster? Half way? It seems to me that changing the adjuster will change the geometry.
I haven't either, and I still don't understand it.A_67vdub wrote:OK, I've never set valvetrain geometry before, but I've read about it and I think I understand it.
I still don't get it. Perpendicular in what sense? Doesn't this mean that your engine has to be perfectly square? If it is tilted a little, how could you tell if the measurement is really "perpendicular?" This is something I don't think I can understand just reading it without someone showing me.So, when the valve is at half lift, a line going from the center of the rocker shaft (the point that the rocker pivots on) to where the adjuster/rocker tip touches the valve should be perpendicular to the valve. Is this correct?
amskeptic wrote:The Hill Billy's Guide To Valve Geometry
Your rocker arm is a hammer. Your valve is a nail.
The hammer has to hit the nail square.
Your arm is a rocker. If you are too far from your nail you will bend it downwards. If you are too close to your nail you will bend it upwards.
You can easily see the arc that the rocker arm describes. You just want the rocker arm to be positioned "square" at half-lift on the valve.
That's all we are doing, trying to get the stupid arc to be exactly at the middle when the valve is half open. Then we get to divide the sideways forces in half so there is a little "up" against the guide and a little "down" against the guide during a valve opening event. If it is not correct, you'll quickly get too much "up" force against the guide or too much "down" force against the guide, and the valve will turn the guide oval, and then the valve will wobble and then the valve will burn and then it will drop and everything...
Colin
LOL! That IS funny! Okay, I figured out the concept by drawing a picture of the arc of a rocker arm. However, I'm still fuzzy on how to actually measure/figure out if the rocker arm is perfectly perpendicular at half lift without the benefit of a few expensive tools. Would this work?amskeptic wrote:The Hill Billy's Guide To Valve Geometry
Your rocker arm is a hammer. Your valve is a nail.
The hammer has to hit the nail square.
Your arm is a rocker. If you are too far from your nail you will bend it downwards. If you are too close to your nail you will bend it upwards.
You can easily see the arc that the rocker arm describes. You just want the rocker arm to be positioned "square" at half-lift on the valve.
That's all we are doing, trying to get the stupid arc to be exactly at the middle when the valve is half open. Then we get to divide the sideways forces in half so there is a little "up" against the guide and a little "down" against the guide during a valve opening event. If it is not correct, you'll quickly get too much "up" force against the guide or too much "down" force against the guide, and the valve will turn the guide oval, and then the valve will wobble and then the valve will burn and then it will drop and everything...
Colin
Just to obfuscate a little for you, I don't do the perpendicularity thing.britegreenVWSB wrote: How do you determine if this line from the valve stem, through the rocker shaft, to the push rod end of the rocker are is TRULY PERPENDICULAR? What on the engine do you use as a reference to DETERMINE whether or not this theoretical line is actually perpendicular? TG