I've got a stock width ball joint beam.
From what I've gathered at the CBperformance website the link pin drop spindles add 1" total to the track width and the ball joint spindles don't. They've only got the disclaimer under the link pin drop spindle page


Anyway, I'll assume I lose 1/2"(12.7mm) per side using 4-lug (4x130 in my case) ball joint front end disc brakes and 2-1/2"(63.5mm) drop spindles from CB.
I've currently got 15"(381mm)x4.5"(114.3mm) chrome rims up front (with 165R-15's aprox. 82 aspect ratio) in addition to the brakes and spindles. 5.5"(139.7mm) width overall and 4.5"(114.3mm) of backspace...1"(25.4mm) of front space. Keep in mind the tire has a lot of side wall roll and the car has been lowered 2-1/2"(63.5mm). So the wheel code would be "15x4.5 4-130 44.45"
I've got stock steel front fenders (US market) `67 and later.
So my final combo give me just a little tire rub on the fender during the most extreme situations...full tank of gas, toolbox, passenger, hard turn, lots of speed, and hard braking. Lower profile tires and narrower tires would both help give me clearance.
If I were to go to a 15"(381mm)x7"(177.8mm) with 52mm offset assuming the same ride height and tire characteristics The tire would be out of the fender (not necessarily when still but under extreme situations) by aprox 0.958"(24.2mm). Must guess the overall rim width so I can only give an approximation. Wheel code of "15x7 5-130 52"
How's my math and findings guys?